Question

NUMERICALS
A car initially at rest travels a distance of 100 m in 5 s
with constant acceleration. Calculate the acceleration
and final velocity after 5 s.​

Answer 1

Explanation:

s=ut+1/2at²

100=1/2a(5)²

a=8m/s²

v=u+at

v=8×5

v=40m/s

Answer 2

Answer:

u = 0m/s

t = 5s

s = 100m

s = ut + 1/2at^2

100 = 0 + 1/2a x 5^2

100 =1/2a x 25

100/25 = 1/2a

4 x 2 = a

8m/s^2 = a

v = u + at

v = 0 + 8x5

v = 40m/s

hope this helps