Question

Numericals.
A current of 1A is drawn by a filament of an electric bulb.
Number of electrons passing through A cross section ot the
filament in 16s would be roughly.​

Answer 1

Explanation:

Given-

I= 1A, t=16 seconds, no. of electrons=?

we know that

Q= I/t

Q= 1/16= 0.0625 C

And we also know that

Q= ne

0.0625= n× 1.6× 10-19

n= 0.0625/1.6× 10-19

n= 0.0390625× 1019 electrons

n= 3.90625× 1017 elecrtrons