Numericals based on Boyle's law:
Please explain in detail.
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Answered by
18
Boyle's law :
For an ideal gas,
P * V = K = constant , at a constant Temperature
Initial Pressure = P1 = 1080 mm Hg
Initial Volume = V1 units
Decrease in volume = 40% of V1.
Final Volume = V2 = V1 - 40/100 * V1 = 0.60 V1
Final Pressure = P2
Applying Boyle's Law:
P2 V2 = P1 V1
=> P2 = P1 V1 / V2
= 1, 080 * V1 / (0.60 V1)
= 1, 800 mm of Hg
Answer 1,800 mm of Mercury column.
For an ideal gas,
P * V = K = constant , at a constant Temperature
Initial Pressure = P1 = 1080 mm Hg
Initial Volume = V1 units
Decrease in volume = 40% of V1.
Final Volume = V2 = V1 - 40/100 * V1 = 0.60 V1
Final Pressure = P2
Applying Boyle's Law:
P2 V2 = P1 V1
=> P2 = P1 V1 / V2
= 1, 080 * V1 / (0.60 V1)
= 1, 800 mm of Hg
Answer 1,800 mm of Mercury column.
kvnmurty:
:-)
Answered by
7
HI,
we know
P 1V1=P2V2
we know that volume has decreased by 40%, thus the volume left was 60% of initial volume
1080 × x=P2 × 0.6x
P2=1800mm of Hg
we know
P 1V1=P2V2
we know that volume has decreased by 40%, thus the volume left was 60% of initial volume
1080 × x=P2 × 0.6x
P2=1800mm of Hg
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