Numericals
How many atoms are required to prepare 60g of HNO3
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in 1 mole of nitric acid there are 5 moles of atoms ie: 1mole H&N
and 3 moles of O atoms
no of moles = 60/63=0.95 moles
it contains 0.95 ×5 moles atoms = 4.76×6.022×10²³ atoms
=28.67× 10²³ atoms are required to prepare this
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