Numericals
How many atoms are required to prepare 60g of HNO3 chemistry class 9
Numerical 1.7
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Answer:
Mr of HNO3 is 1+14+3*16 = 63
60/63 = #of moles = 0.952380952
0.952380952 * #Avogadro’s = #of molecules = 5.7142857x10^23
5.7142857x10^23 x #of atoms in one molecule = #of atoms = 2.8571429x10^24 atoms
Explanation:
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