(Numericals on reflection)
{1} A 4cm tall tube light is placed at 45.7cm in front of a concave mirror of focal length 15.2cm. At what distance from the mirror should a screen be placed to obtain a sharp image? Find the nature and size of the image.
{2} Determine the image distance and image height for a 5cm tall object placed 30 cm from a concave mirror having a focal length of 15cm.
{3} A magnified inverted image is located t a distance of 32cm from a concave mirror of focal length 12cm. Determine the object distance and tell whether the image is real or virtual.
Pls solve this three numericals
Answers
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Answer:
answer 1 the image distance is 22.8 cm and the image size is 1.99 CM
answer 2 Where f is focal length, v is image distance from the mirror and u is object distance from the mirror (concave). Substitute the known values in the above formula to find the value of 'v' i.e. image distance from the mirror. Therefore, the image distance from the concave mirror is -22.5 cm
answer 3 Given,
Image distance, v=32 cm
Focal length, f=12 cm
From mirror formula,
f
1
=
v
1
+
u
1
⇒
−12
1
=
−32
1
+
u
1
⇒
u
1
=
32
1
−
12
1
=
32×12
12−32
=−
32×12
20
=
96
−5
u=
5
−96
=−19.2 cm
Explanation:
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