NUMERICALS.
Q3.A child marches at the speed of 1.5m/s. What distance will he cover in two hour?
Q4.A person walks 30 meters east, then walks 40 meters north. Determine distance and
displacement.
Q5.A runner travels around rectangle track with length = 50 meters and width = 20 meters. After
travels around rectangle track two times, runner back to starting point. Determine distance and
displacement.
Answers
Answered by
1
Answer:
3. 1.5*60(for a minute)*60(for an hour)*2(for 2 hours)=10.8kms
4. Distance covered is scalar and independent of direction. So distance is 30+40=70m
Displacement is vector and its relative to the starting point. It is the shortest path between 2 points. Use pythagoras theorem for it.
Displacement=✓30^2+40^2 = 50m
5. Distance = Perimeter of rectangular field*2
Distance = 280m
Displacement is 0m, that is, shortest distance between starting and ending point.
Answered by
1
A3 Convert 2 hours in seconds=2X3600=7200 seconds
Distance=Speed X Time
=1.5 X 7200
=10800
Distance=Speed X Time
=1.5 X 7200
=10800
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