Question

NUMERICALS.

Q3.A child marches at the speed of 1.5m/s. What distance will he cover in two hour?

Q4.A person walks 30 meters east, then walks 40 meters north. Determine distance and

displacement.

Q5.A runner travels around rectangle track with length = 50 meters and width = 20 meters. After

travels around rectangle track two times, runner back to starting point. Determine distance and

displacement.

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Answer 1

Answer:

3. 1.5*60(for a minute)*60(for an hour)*2(for 2 hours)=10.8kms

4. Distance covered is scalar and independent of direction. So distance is 30+40=70m

Displacement is vector and its relative to the starting point. It is the shortest path between 2 points. Use pythagoras theorem for it.

Displacement=✓30^2+40^2 = 50m

5. Distance = Perimeter of rectangular field*2

Distance = 280m

Displacement is 0m, that is, shortest distance between starting and ending point.

Answer 2

A3 Convert 2 hours in seconds=2X3600=7200 seconds

Distance=Speed X Time
=1.5 X 7200
=10800