Question

numericals
the velocity of a car increases from 36 km/h to 72 km/h in 10s .find the acceleration of the car ​

Answer 1

Answer:

rate of change in velocity is acceleration,

v₁=36km/h        t₁=0s

v₂=62km/h       t₂=10s

acceleration=v₂-v₁/t₂-t₁

                   =72-36/10-0

                   =36/10

⇒∴a=3.6m/s²

HOPE IT HELPS U...

Answer 2

• Explanation:

this is help to solve question