Question

numo=0
while [ "$numo" -lt 3 ]
do
numo=$((numo+1))
numt=0
while [ "$numt" -lt 3 ]
do
numt=$((numt+1))
if [ $numt -eq 2 ]; then
continue
fi
echo "$numo"
done
done

Answer 1

Answer:

Please tell the chapter also

Answer 2

Answer: bash main.sh

1 1

2 1

3 1

Explanation: