Question

nut cracker of length 9 cm has its effort situated at a distance of 6 cm from the

load . Calculate the velocity ratio of nut cracker ​

Answer 1

Answer:

total length of nut cracker=9cm

load arm=6cm

effort arm=9-6=3cm

Mechanical advantage=effort/load

=3/6=0.5cm

Answer 2

Given:

Nut cracker of length 9 cm has its effort situated at a distance of 6 cm from the load.

To find:

Velocity Ratio of nut cracker.

Calculation:

Nut cracker is a 2nd order lever , such that , the velocity ratio can be expressed as :

$\boxed{ \sf{VR = \dfrac{distance \: moved \: by \: effort}{distance \: moved \: by \: load} }}$

$= > \sf{VR = \dfrac{effort \: arm}{load \: arm} }$

$= > \sf{VR = \dfrac{9 - 6}{6} }$

$= > \sf{VR = \dfrac{3}{6} }$

$= > \sf{VR = 0.5 }$

So, final answer is:

$\boxed{\rm{Velocity \: Ratio = 0.5 }}$