Question

O 10 ml of baryta solution 20 ml of 0.1 n h2so4 was added and the excess acid required 4 ml of 0.1n naoh. The molarity of baryta ba(oh)2 solution is

Answer 1

0.1 M H2SO4= 0.2 N H2SO4 0.1 M NaOH= 0.1 N NaOH V1. ... Now, let x ml of H2SO4 is added more. ... volume of H2SO4 is required to completely neutralize