O: 12, Marks : 2
1. Solution of the recurrence relation Sk+2- Sk+1-2 Sk=4 and
So= -1, S1= 3, k2> 0 is
Sk=(-1)(-1)k+2(2)k_2
Sk=(2)k+212)k+2
Sk=(-1)k+2(2)k-2
Sk=(2)k+2(2k-2
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