Question

o.126 g of an acid requires 20 ml of 0.1N Naoh for complete neutralization .eq.weight of the acid is​

Answer 1

Answer:

63

Explanation:

A substance's equivalent weight is defined as that substance weight displaces or combines with 1 part by hydrogen weight or 8 parts by oxygen weight or 35.5 part by chlorine weight.

From the given,

Weight of acid = 0.126 g

Volume = 20 ml

Let's convert into liters..

For neutralization, 20 ml of 0.1N NaOH requires 0.1N acid.

Normality of acid = 0.1N

Let's calculate the acid's equivalent weight.

Equivalent weight= Weight of an acid /Normality×Volume

=0.126×1000/0.1×20

=63

Therefore, equivalent weight of acid is 63.

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