Question

O
2003
Consider an integer array int arr[4]
[5]. If base address is 1020, find the
address of Element arr[3][4] with row
major representation. Size of int is 2
bytes.
1020
O
1038
O
1039
1058​

Answer 1

Answer:

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Answer 2

Answer:

The address of A [3] [4] is 1058

Explanation:

We know that, in row Major,

Address of A [ i ] [ j ] = B + W [n (i - L₁) +(j - L₂)]

where, B = Base address

W = Size of each cell

n = No. of columns of the array

i = no. of rows of the array whose address is to be found

j = no. of columns of the array whose address is to be found

L₁ = Lower index of the row of the array

L₂ = Lower index of the column of the array

Therefore, on substitution,

A [3] [4] = 1020 + 2 [5 (3 - 0) +(4 - 0)]

            = 1020 + 2[15 + 4]

            = 1020 + 2 [19]

            = 1020 + 38

            = 1058

Therefore, the address of A [3] [4] is 1058