Question

O
2008 BF
7.An object travels 40m in 5 sec and then another 80m in 5 sec. The average speed of the object is​

Answer 1

Given :

• An object travels 40m in 5seconds and
• 80m in 5 seconds

To find :

Average speed of the object

Formula to know :-

${Average\:speed} = \dfrac{Total\:distance}{Total\:time}$

SOLUTION;

Total distance = 40m+80m

Total distance = 120m

Total time = 5sec+5sec

Total time = 10 sec

${Average\:speed} = \dfrac{Total\:distance}{Total\:time}$

$= \dfrac{120m}{10sec}$

$= 12m/s$

So the speed of object is 12m/s

Know more :-

• Average velocity = Total displacement/total time
• 1km/hr = 5/18 m/s
• 1m/s = 18/5 km/hr
• Distance = Speed × time
• Time = Speed /time

Answer 2

Question:

An object travels 40m in 5 sec and then another 80m in 5 sec. The average speed of the object is?

Given:

Object travels $\mathsf{40\: meter}$ in $\mathsf{5\: seconds}$ and then travels $\mathsf{80\: meters}$ in $\mathsf{5\: seconds}$

To Find:

Average speed of object.

Explanation:

For finding the average speed of the object we have to first find the total distance and total time travelled by the object. Then divide Total distance by total time.

Solution:

$:\implies\mathsf{Total\: Distance=40m+80m=120m}$

$:\implies$ $\mathsf{Total\: Time=5sec+5sec=10sec}$

Now,

$\mathsf{Average\: speed=\frac{Total\: distance}{Total\: time}}$

ㅤㅤㅤㅤㅤㅤㅤ$\mathsf{=\frac{120}{10}}$

ㅤㅤㅤㅤㅤㅤㅤ$\mathsf{=12m/sec}$

Final Answer:

The Average speed of the object is $\mathsf{12m/sec}$

Abbreviation:

$\mathsf{-m=Meter}$

$\mathsf{-sec=Second}$

Formula Used:

$\mathsf{Average\: speed=\frac{Total\: distance}{Total\: time}}$