Math, asked by AnshumanKapoor, 9 months ago

O
3. Two adjacent angles of a parallelogram are (3x - 4) and (3x + 160)", Find
the value of x and hence measure of each of its angles.​

Answers

Answered by Bhargavigaddam654321
1

Answer:

Adjacent angles sum is 180

(3x-4)+(3x+160)=180

3x-4+3x+160=180

3x+3x-4+160=180

6x+156=180

6x=180-156

6x=24

x=4

Since

3x-4 substitute x value

3(4)-4

12-4

=8

3x+160

3(4)+160

12+160

172

Hence

8+172=180

Answered by mvktulasimallikharrj
2

Answer:

Hey it's easy you just need to know about sum of adjacent angles in parallelogram is180°

(3x-4)+(3x+160)=180°

3x-4+3x+160=180°

6x-156=180°

6x=180+156

6x=336

x=336/6=56

so,(3x-4)=3(56)-4=164

and(3x+160)=3(56)+160=328

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