Question

o 4 is sum plz me spammer will be reported
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Answer 1

$\huge{\underline{\underline{\bf{ SoLuTiOn\: - }}}}♡⇒$

Now, perimeter of the triangle = (15+16+17) m = 48 m

∴ Semi-perimeter of the triangle = s = 48/2 = 24 m

By Heron’s formula,

Area of the triangle = √(s(s – a)(s – b)(s – c)) ,

where a, b and c are the sides of triangle

= √(24(24 – 15)(24 – 16)(24 – 17))

= 109.982 m2

Let B, C and H be the corners of the triangle on which buffalo, cow and horse are tied respectively with ropes of 7 m each.

So, the area grazed by each animal will be in the form of a sector.

∴ Radius of each sector = r = 7 m

Let x, y, z be the angles at corners B, C, H respectively.

∴ Area of sector with central angle x,

= ½ (x/180) × πr2 = (x/360) × π(7)2

Area of sector with central angle y,

= ½ (y/180) × πr2 = (y/360) × π(7)2

Area of sector with central angle z,

= ½ (z/180) × πr2 = (z/360) × π(7)2

Area of field not grazed by the animals = Area of triangle – (area of the three sectors)

(109.982)−[(x360×π72)+(y360×π72)+(z360×π72)](109.982)−[(x360×π72)+(y360×π72)+(z360×π72)]

=>(109.982)−[(x+y+z360×π72)(109.982)−[(x+y+z360×π72)

=>(109.982)−[(180360×22749)](109.982)−[(180360×22749)]

=> 109.892 – 77

=> 32.982 cm2

• Answer : -

Area of field not grazed by the animals = 32.982 cm2 . . .