English, asked by tanmaisree9, 8 months ago

O
(5,6)
3. The equation of the tangent to the circle X^2+Y^2-6X+4Y-12=0 at (7.-5) is 1 point
4X-3Y+7=0
O
4X-3Y-43=0
O =
4X+3Y-7=0
O 4X+3Y+43=0

Answers

Answered by Chauhanpayal2

1

Answer:

don't know sorry really sorry

Answered by sranjan87

0

I don't know sorry

jakkak

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