Question

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5. A line segment AP stands at point P of a straight line BC such that ZAPB = 5x - 40° and
ZAPC = x + 10°; find the values of x and angle APB.​

Answer 1

Answer:

Step-by-step explanation:

AP stands on BC at P and

∠APB = 5x – 40°, ∠APC = x + 10°

(i) ∵ APE is a straight line

∠APB + ∠APC = 180°

⇒ 5x – 40° + x + 10° = 180°

⇒ 6x - 30°= 180°

⇒ 6x = 180° + 30° = 210°

x = \frac { 210 }{ 6 }° = 35°

(ii) and ∠APB = 5x – 40° = 5 x 35° – 40°

= 175 ° – 140° = 135°

Refer to the attachment

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Answer 2

Step-by-step explanation:

here your solution

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