Question

o.5 amphere current has been flowing in a circuit for 20 minutes calculate the number of electrons flowing from one end to the another end of the circuit ​

Answer 1

given- I(electric current)=0.5A

and,. time=20min=20*60=1200s

we know that, I=ne/t

e= 1.6*10-19C {charge on one

electron}

so, 0.5=n*1.6*10-19/1200

n*1.6*10-19= 600

n= 6*100/1.6*10-19

n=3.75*10^21 electrons

Answer 2

Given,

The total current flowing in a circuit = 0.5 A

Time of flow if current = 20 minutes

To find,

The total number of electrons flowing from one end to another end of the circuit.

Solution,

We can simply solve this numerical problem by using the following process:

Mathematically,

Current flowing through a circuit (I)

= {(number of electrons flowing (n)}x {charge in each electron(n)} / {duration of the flow of current(t)}

=> {(number of electrons flowing (n)} = {Current flowing through a circuit (I)} x {duration of the flow of current(t)} / {charge in each electron(n)}

Now, according to the question;

The total number of electrons flowing from one end to another end of the circuit

= {Current flowing through a circuit (I)} x {duration of the flow of current(t)} / {charge in each electron(n)}

= 0.5 A x 20 minutes / 1.6 x 10^-19 C

= 0.5 A x 1200 s / 1.6 x 10^-19 C

= 3.75 x 10^21

Hence, the total number of electrons flowing from one end to another end of the circuit is equal to 3.75 x 10^21.