Question

O ABCD & ampe. AB IICD-
AB=10, CD = 25.
BC & AD are
13 & 14cm
find area of trapezium​

Answer 1

$\color{red}{Answer}$⬇️

$\color{green}{Area \: of \: trapezium} \: = > {a+b} \times h\div 2$

=> (10 +25)/2 × 12.25 cm²

=> [35 × 12.25]/2 cm²

=> 214.38 cm².

KINDLY REFER TO THE ATTACHMENT⬆️

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Answer 2

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