Question

O. An electric pole casts a shadow of length 18 m at a time when a tree 12 m high casts a
shadow 9 m long. Find the height of the pole. (Hint: Height of the pole : length of the
Shadow of the pole height of the tree : length of the shadow of the tree]
2 runs in 6 overs and Anup made 63 runs in 7 overs. Who made more runs
​

Answer 1

height is the tree: 12m

shadow cast by it:9m

height of the pole: x

shadow of pole:18m

x= 12*9/18

x= 12*1/2

x=12/2

x=6

answer=6m

Answer 2

Anup score more runs and Height of pole is 24 m.

Step-by-step explanation:

Since we have given that

Length of shadow = 18 m

Height of tree = 12 m

Length of shadow of pole = 9 m

According to question, we get that

$\dfrac{x}{18}=\dfrac{12}{9}\\\\\dfrac{x}{18}=\dfrac{4}{3}\\\\x=6\times 4\\\\x=24$

2 runs in 6 overs and Anup made 63 runs in 7 overs. Who made more runs

Anup's average  is given by

$\dfrac{63}{7}=9$

Average is given by

$\dfrac{6}{2}=3$

Hence, Anup score more runs and Height of pole is 24 m.

# learn more:

An electric pole Casts a shadow of length 15 M at a time when a tree 20 m high Casts a shadow of length 18 M find the height of pole​

https://brainly.in/question/8716417