O are any two points
6
(a) In the figure (1) given below, ABCD is a parallelogram. P, Q are any
on the sides AB and BC respectively. Prove that
area of ACPD = area of AAQD.
Answers
Answered by
1
Step-by-step explanation:
I THINK YOUR QUESTION IS WRONG AND THE FIGURE IS ALSO NOT GIVEN BUT STILL,
LET,ABCD IS A PARALLELOGRAM,
WHERE P LIES ON AB AND Q LIES ON BC
THEREFORE,
AB=CD (OPPOSITE SIDES)
AC=BD(" ")
angle A=angle D
Area of triangle ACPD IS EQUAL TO THE AREA OF TRIANGLE BDQD
HOPE IT HELPS!
Similar questions