Question

o bodies A and B are attached to the end of a string which passes
mulley, so that they hang vertically. If the mass of the body B is 4 kg find the
mass of the body A which moves up with an acceleration of 0.5ms-2
take g = 10 ms-2
​

Answer 1

Given :

Two bodies A and B are attached to the end of a string which passes over a pulley.

Acc. of the system = 0.5 m/s²

Mass of body B = 4kg

To Find :

Mass of body A

Solution :

❒ In this question, body A moves upward and body B moves downward. It means that mass of body B is greater than the mass of body A.

• Here, force acts on both bodies is weight force or better to say force due to gravity.

As per newton's second law of motion, force is measured as the product of mass and acceleration$.$

Mathematically, F = m a

Net force on the system will be,

• Fₙ = m₂g - m₁g

» m₂ denotes masa of body B

» m₁ denotes mass of body A

➠ m₂g - m₁g = (m₁ + m₂) a

➠ (4)(10) - 10m₁ = (m₁ + 4)(0.5)

➠ 40 - 10m₁ = 0.5m₁ + 2

➠ 40 - 2 = 10m₁ + 0.5m₁

➠ 38 = 10.5m₁

➠ m₁ = 38/10.5

➠ m₁ = 3.62 m/s²

Answer 2

Given :

Two bodies A and B are attached to the end of a string which passes over a pulley.

Acc. of the system = 0.5 m/s²

Mass of body B = 4kg

To Find :

Mass of body A

Solution :

❒ In this question, body A moves upward and body B moves downward. It means that mass of body B is greater than the mass of body A.

Here, force acts on both bodies is weight force or better to say force due to gravity.

As per newton's second law of motion, force is measured as the product of mass and acceleration..

Mathematically, F = m a

Net force on the system will be,

Fₙ = m₂g - m₁g

» m₂ denotes masa of body B

» m₁ denotes mass of body A

➠ m₂g - m₁g = (m₁ + m₂) a

➠ (4)(10) - 10m₁ = (m₁ + 4)(0.5)

➠ 40 - 10m₁ = 0.5m₁ + 2

➠ 40 - 2 = 10m₁ + 0.5m₁

➠ 38 = 10.5m₁

➠ m₁ = 38/10.5

➠ m₁ = 3.62 m/s²