Question

o) Construct a quadrilateral ABCD in which AB = BC = CD = DA - 5 cm and
ZA = 120°. What type of quadrilateral is it?​

Answer 1

Step-by-step explanation:

Steps :

Draw AB = 4 cm.

At A, draw ∠PAB = 120°.

At B, draw ∠QBA = 60°.

From BQ, cut BC = 4.5 cm.

From C, draw an arc of radius 5 cm which meets AP at D.

Join CD.

Thus ABCD is the required quadrilateral