Question

O
D
Q10
1 point
To The
factorization of 2x²+2x+3 y is
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Answer 1

Step-by-step explanation:

ANSWER

Given equation:

2x

2

+xy−3y

2

+x+ay−10=(2x+3y+b)(x−y−2)

⇒2x

2

+xy−3y

2

+x+ay−10=2x

2

+3xy+bx−2xy−3y

2

−by−4x−6y−2b

⇒2x

2

+xy−3y

2

+x+ay−10=2x

2

+xy−3y

2

+(b−4)x−(b+6)y−2b

Comparing the coefficients of x,y and constants will get:

b−4=1..(i)

−(b+6)=a..(ii)

−2b=−10..(iii)

From eq(1), we get

⇒b=5

Now put b in eq(2), we get

⇒−(b+6)=a

⇒a=−11

From eq(3), we get

⇒−2b=−10

⇒b=5

Hence values of a,b are −11,5

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