Question

O
HN.
i) LiAlH4, Major products is/are
ii) H2O
excess
O
1)
HN
2) HN.
+
HN
OH
3)
OH
HN
TERE
4) HON
OH​

Answer 1

Answer

HN+ Oh

Explanation:

As we know that LiAlh4 is a reducing agent it gives H- and O is more6s electroegative hence it's going to break the bond and leave place for Hn and the o released will make bond with H.

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Answer 2

Explanation:

$\sf \circ\ {Find\ all\ points\ of\ discontinuous\ of\ f,\ where\ f\ is\ defined\ by,}$

$\sf f(x)\ = \begin{cases} &\sf{2x\ +\ 3,\: \: \: \: \: \: \: \: if\ x \leq 2} \\ \\ &\sf{2x\ -\ 3,\: \: \: \: \: \: \: \: if\ x > 2} \end{cases}$