Question

o in an enamination, a girl scored 39.5 of mauimu.
marks and pass by 18 marks, a boy scored 23% of
marks and fails by ly marks. what is the percentage
required to pass​

Answer 1

Step-by-step explanation:

Let the maximum marks be x.

Then Pass mark for the 1st student =

100

20

×x+5

Pass mark for the 2nd student =

100

30

×x−20

Since pass marks are same for both the students

100

20x

+5=

100

30x

−20

⇒

100

10x

=25⇒x=250

∴ Pass mark =

100

20

×250+5=55

Pass percentage =

250

55

×100+5=22%