Question

o is a centre of circle of radius 5cm op is perpendicular ab and oq perpedicular cd ab patallel to cd ab=6cm cd=8cm determine pq​

Answer 1

length of pq = 7cm

Step-by-step explanation:

since, oq is perpendicular to cd

therefore cq= dq (since q is the midpoint)

therefore cq= 4cm

similarly, ap= 3cm

therefore by pythagoras theorm

in triangle cqo

co² = oq²+cq²

5² = 4² + cq²

cq = 3cm

similarly in triangle apo

op² = oa²- po²

op = 4cm

pq = 7cm