o is a centre of circle of radius 5cm op is perpendicular ab and oq perpedicular cd ab patallel to cd ab=6cm cd=8cm determine pq
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length of pq = 7cm
Step-by-step explanation:
since, oq is perpendicular to cd
therefore cq= dq (since q is the midpoint)
therefore cq= 4cm
similarly, ap= 3cm
therefore by pythagoras theorm
in triangle cqo
co² = oq²+cq²
5² = 4² + cq²
cq = 3cm
similarly in triangle apo
op² = oa²- po²
op = 4cm
pq = 7cm
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