O is a point in the exterior of triangleABC than show that 2(OA+OB+OC)>AB+BC+CA
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Let the units place be x
Tens place will be x+3
10(x+3)+x+10x+x+3 = 143
10x+30+x+10x+x+3=143
On substituting we get
22x=143-33
22x=110 x=5
Units place is 5
Tens place is x+3= 5+3 =8
Tens place will be x+3
10(x+3)+x+10x+x+3 = 143
10x+30+x+10x+x+3=143
On substituting we get
22x=143-33
22x=110 x=5
Units place is 5
Tens place is x+3= 5+3 =8
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