Question

O is a point inside ∆ABC.OX,OY &OZ are perpendicular from O to the sides BC,CA,AB. Now prove that AZ^2+BX^2+CY^2=AY^2+CX^2+BZ^2.
${az }^{2} + {bx }^{2} + {cy}^{2} = {ay}^{2} + {cx}^{2} + {bz}^{2}$

Answer 1

Hello friends....

Now add corresponding sides and you will get the answer....

Hope this helps you....