Question

O is any point in the interior of rectangle ABCD Prove that OB² +OD²=OC²+OA²

Answer 1

Answer:

hope it helps you

Step-by-step explanation:

Through O, draw PQ || BC so that P lies on AB and Q lies on DC. Now, PQ || BC Therefore, PQ ⟂ AB and PQ⟂DC (∠B = 90° and ∠C = 90°) So, ∠BPQ = 90° and ∠CQP = 90° Therefore, BPQC and APQD are both rectangles. Now, from ΔOPB, OB2 = BP2 + OP2 .....(1)

Answer 2

Answer:

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