o is any point within a triangle ABC whose sides are 4cm 5cm 7cm pove that oa +ob+oc is greater than 8 cm
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let AB =5cm, BC= 4cm, AC =7cm
now, since sum of two sides of a triangle is greater than the third side therefore
OA+OB>5
OB+OC>4
OC+OA>7
Adding all the three equations
2(OA+OB+OC)>5+4+7
OA+OB+OC>16/2
so, OA+OB+OC>8
now, since sum of two sides of a triangle is greater than the third side therefore
OA+OB>5
OB+OC>4
OC+OA>7
Adding all the three equations
2(OA+OB+OC)>5+4+7
OA+OB+OC>16/2
so, OA+OB+OC>8
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