Math, asked by ms1763334, 1 day ago

O is any point within the parallelogram ABCD. Proved that , ∆AOB + ∆ COD = ∆ AOD + ∆ BOC

Answers

Answered by queensiyabhatt

1

Answer:

in givenfigure;Quadrilateral ABCD is a parallelogram so AD||BC DAC= ABC-------(ultranet angle) ACB=32^°AOB+ BOC=180^°---(straight

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