O is any point within the triangle ABC. The perpendicular OM,ON to AB and BC are equal.Prove that BO is the Bisector of ∆ ABC.
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Answer:I think we have to prove BO is the bisector of angle ABC !
Step-by-step explanation:In ∆OMB and ∆ONB
angle OMB=angle ONB (EACH 90°)
OM=ON (GIVEN)
BO=OB (COMMON)
angle OBM=angle OBN (by CPCT)
Hence proved BO is the bisector of angle ABC
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