.. O is centre of circle, ABCD is a square inscribed in the circle. Find the ratio of the perimeter of ABCD and perimeter of the semicircle ABC
Answers
Answered by
2
Solution :-
Let us assume that, the radius of circle with centre O is r cm and side of square is a cm .
so,
→ Diameter of circle = Diagonal of square .
→ 2r = √2a
→ a = (2r/√2)
→ a = √2r
then,
→ Perimeter of ABCD : Perimeter of semicircle ABC
→ 4a : (πr + 2r)
→ 4 * √2r : r(π + 2)
→ 4√2 : (π + 2) (Ans.)
Learn more :-
Diagonals AC and BD of quadrilateral ABCD meet at E. IF AE = 2 cm, BE = 5 cm, CE = 10 cm, 8 सेमी.
https://brainly.in/question/27312677
Let abcd be a rectangle. the perpendicular bisector of line segment bd intersect ab and bc in point e and f respectively...
https://brainly.in/question/27813873
Attachments:
Similar questions
Hindi,
7 days ago
Hindi,
7 days ago
Physics,
7 days ago
Computer Science,
15 days ago
CBSE BOARD X,
15 days ago
Geography,
8 months ago