o is centre of circle.Find the length of radius , if the chord of length 16cm is at a distance of 9 cm from the centre of the circle.
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OA is radius
O is the centre of circle.
AB is the chord and OC⊥AB
Segment between the centre of circle bisect the chord into two parts
∴AC=CB=
2
1
AB
∴AC=CB=12
Now ΔOCB is right angle triangle
∴ by Pythagoras theorem
(OC)
2
+(AC)
2
=(OA)
2
(9)
2
+(12)
2
=(OA)
2
81+144=(OA)
2
225=(OA)
2
∴ Taking square root both sides
∴15=OA
∴ The radius of circle 15cm
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