Question

O is centre of circle. Find the length of radius, if the chord of length 16 cm is at a distance of 9 cm from the center of the circle. ​

Answer 1

Answer:

OA is radius

O is the centre of circle.

AB is the chord and OC⊥AB

Segment between the centre of circle bisect the chord into two parts

∴AC=CB=21AB

∴AC=CB=12

Now ΔOCB is right angle triangle

∴ by Pythagoras theorem

(OC)2+(AC)2=(OA)2

(9)2+(12)2=(OA)2

81+144=(OA)2

225=(OA)2

∴ Taking square root both sides

∴15=OA

∴ The radius of circle 15cm

Step-by-step explanation:

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Answer 2

Answer:

OA is radius

O is the centre of circle.

AB is the chord and OC⊥AB

Segment between the centre of circle bisect the chord into two parts

∴AC=CB=

2

1

AB

∴AC=CB=12

Now ΔOCB is right angle triangle

∴ by Pythagoras theorem

(OC)

2

+(AC)

2

=(OA)

2

(9)

2

+(12)

2

=(OA)

2

81+144=(OA)

2

225=(OA)

2

∴ Taking square root both sides

∴15=OA

∴ The radius of circle 15cm