Question

O is centre of the circle . AB and PQare two chords of equal distance from the centre .AB=12,OC=8.what is the length of PQ?

Answer 1

  l(AB) =12 cm                                                        

l(AC)= 6cm

l(OC)=8cm

By pythagoras theorem,

(OA)² = (OC)² + (AC)²            

(OA)² = 8² + 6²

         = 64 + 36

(OA)² = 100

∴ OA = 10cm

∴ OP = 10cm   --------- (radius of the same circle)

similarly, PQ = 12cm