Math, asked by dilipkhamkar06, 10 months ago



O is centre of the circle. Find the length of
radius, if the chord of length 24 cm is at a
distance of 9 cm from the centre of the circle.
24 cm​

Answers

Answered by thempara75
4

Answer:Given ' O ' is centre of the circle.

OM = 9 cm

Chord ( AB ) = 24 cm

Radius = OA

OM perpendicular to AB

and

OM bisects AB .

AM = AB/2 = 24/2 = 12 cm

In ∆AOM ,

<AMO = 90°

By Phythogarian theorem ,

OA² = AM² + OM²

= 12² + 9²

= 144 + 81

= 225

OA² = 225

OA = 15 cm

Therefore ,

Radius ( OA ) = 15 cm

Read more on Brainly.in - https://brainly.in/question/4841788#readmore

Step-by-step explanation:

Answered by GodAryan
2

Step-by-step explanation:

the perpendicular line drawn from the centre to the chord bisects the chord this property tells us that the line which is from centre is bisecting the chord A and B and a and b is equal distributed from 24 is equal to 12 cm

12cm

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