Question

O is centre seg PQ is diameter and AQ is chord.OP =3 and m ( arc PM)= 120 determine AP​

Answer 1

AP = 4√3 cm

Step-by-step explanation:

O is centre seg PQ is diameter

OP = 3 cm

Radius = 3 cm => Diameter = 6 cm

=> PQ = 6 cm

AQ ia tangent => ΔAPQ is right angle triangle

m ( arc PM)= 120 °

=> in Δ MOP

∠MOP = 120°

OM = OP Radius

=> ∠OMP = ∠OPM

∠OMP +  ∠OPM  + ∠MOP = 180°  ( sum of angles of triangles)

=> ∠OPM +  ∠OPM  + 120° = 180°

=> 2∠OPM  = 60°

=> ∠OPM  = 30°

=> ∠OPA = 30°

Cos 30° = PQ/AP

=> √3/2  = 6/AP

=> AP = 12/√3

=> AP = 4√3

AP = 4√3 cm

Learn more:

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Answer 2

Answer:

amol here is ur answer

along amitnrw sirs method u can also apply this one

amitnrw is this method ryt as well?

just forgive me for sequence of pics

they are not in chronological order but answer at the end turns out to be same