O is circumcentre of an isosceles triangle abc. ab=ac=17 bc=6 find radius of the circle.
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From the diagram attached:
Cos Theta = 3/17
Meaning, Theta = 79.84 degree
By the law of Sine
b/Sin B = 2R
Where R is the radius of the circumcircle
17/Sin 79.84 = 2R
17.27 = 2R
R = 17.27/2
R = 8.635 cm
∴ The radius of the circle = 8.635 cm
Cos Theta = 3/17
Meaning, Theta = 79.84 degree
By the law of Sine
b/Sin B = 2R
Where R is the radius of the circumcircle
17/Sin 79.84 = 2R
17.27 = 2R
R = 17.27/2
R = 8.635 cm
∴ The radius of the circle = 8.635 cm
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