Question

O is the center of circle RM tangant, OR= 10, Radius=5 find RM​

Answer 1

Answer:

Step-by-step explanation:

∠OMR=∠ONR=90  

o

 

OM=5 cm    OR=10cm

OR  

2

=OM  

2

+MR  

2

 

MR=  

OR  

2

−OM  

2

 

​  

=  

10  

2

−5  

2

 

​  

=5  

3

​  

 cm

(2) in right △OMR

tan∠MRO=  

MR

OM

​  

 

tan∠MRO=  

5  

3

​  

cm

5 cm

​  

=  

3

​  

 

1

​  

 

(3) ∠MRO=30  

o

 

∠MRN=∠MRO+∠NRO=30  

o

+30  

o

=60

∠MRN=60  

o