o is the center of the circle. aob =110° . find m(arc AMB)
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Answered by
2
Step-by-step explanation:
Given,
angle at centre ∠AOB=110
o
angle at circumference ∠ACO
Now,
we know that the angle at the centre is twice the angle at the circumference subtended by the same arc.
Therefore,
∠AOB=2∠ACO
⟹110
o
=2∠ACO
⟹∠ACO=
2
110
o
=55
o
Now,
∠COA+∠AOB=180
o
⟹∠COA=180
o
−110
o
=70
o
In△AOC,
∠AOC+∠ACO+∠CAO=180
o
⟹70
o
+55
o
+∠CAO=180
o
⟹∠CAO=55
o
Answered by
1
Step-by-step explanation:
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