Question

O is the center of the circle <AXB = 130º If so <AYB, <AOB See these​

Answer 1

Step-by-step explanation:

∠ADC=21∠AOC

(Angle subtended by a chord on mayor area is half of that subtended on center)

∴∠ADC=21×130=65∘

Now, ADCB is cyclic quadrilateral ⇒ 

Sum of opposite Angles is 180∘

∴∠ABC+∠ADC=180∘

∠ABC+65=180∘

∠ABC=115∘