O is the center of the circle of radius 5cm.T is a point such that ot=13cm and ot intersects the circle at
e. If ab is the tangent to the circle at
e.Find the length of ab
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OP is equals to a radius is equals to 5 let AE equals to BE be x.
in triangle OPT, OP²+OT²=PT²
Then, PT=12cm.
Now, AT=12-x and AE=x
And TE=13-5=8cm.
Now in triangle AET, AT²=AE²-ET²
x= 10/3cm.
AB=AE+ BE =2x=2×10/3=20/3cm.
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