Math, asked by pranika202, 21 days ago

'o' is the center of the circle whose radius is 10 cm find the distance of the chord from the center if the length of the is 12 cm​

Answers

Answered by Anonymous
0

Answer:

  1. Distance of the centre to the chord = AB. CD is perpendiculaar to the chord AB. Perpendicular drawn from the centre of the circle to the chord bisects the chord. Thus, distance of the chord from the centre is 8 cm.
Answered by ғɪɴɴвαłσℜ
2

\sf{\huge{\underline{\pink{Given :-}}}}

  • 'O' is the center of the circle whose radius is 10 cm.

  • The center if the length of the chord is 12 cm.

\sf{\huge{\underline{\orange{To\:Find :-}}}}

  • The distance of the chord from the center.

\sf{\huge{\underline{\red{Answer :-}}}}

The distance of the chord from the center be x,

According to the question ,

'O' is the center of the circle whose radius is 10 cm.

  • R = 10 cm

The center if the length of the chord is 12 cm.

We know that, the length of the chord of a circle is

 \sqrt{2( {r}^{2} -  {d}^{2}  )}

➝ 12 =  \sqrt{2( {10}^{2} -  {d}^{2}  )}

➝ 12 = 2 \sqrt{100 -  {d}^{2} }

➝ 12/2 = \sqrt{100 -  {d}^{2} }

➝ 6 = \sqrt{100 -  {d}^{2} }

➝ (6)² = 100 - d²

➝ 36 = 100 - d²

➝ d² = 100 - 36

➝ d² = 64

➝ d = √64

d = 8 cm

The distance of the chord from the center is 8 cm .

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