O is the centre and area of sector APBO is 5/18 of the area of the circle. Find the value of x
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Given : area of sector APBO is 5/18 of the area of the circle.
Let us consider subtended angle as "x".
area of sector = 5/18 area of the circle.
x×πr²/360 = (5/18) πr²
x/360 = (5/18)
x = (360×5)/18
x = 20×5
x = 100°
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