Question

O is the centre, ∠AOB = 120°, find ∠BAC.
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Answer 1

Step-by-step explanation:

ABCD is a cyclic quadrilateral. we have

∠ABC+∠ADC=180

o

∠ABC=180

o

−120

o

=60

o

Also ∠ACB=90

o

( angle on a semi circle )

In ΔABC we have

∠BAC+∠ACB+∠ABC=180

o

∠BAC+90

o

+60

o

=180

o

∠BAC=180

o

−150

o

=30

o

Answer

Answer 2

Answer:

answer = 30

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