Question

O is the centre of a circle and AB is the diameter. ABCD is a cyclic quadrilateral. Angle ABC is 65 degree and angle BAD is 40 degree then what will be the measure of angle BCD?​

Answer 1

Answer:

angle BCD= 140°

Step-by-step explanation:

Angle BAD + Angle BCD = 180° (since, in a cyclic quadrilateral sum of opposite angles are 180°)

40°+ angle BCD= 180°

angle BCD= 180°- 40°

Angle BCD= 140°

Hope it helps!

Answer 2

Step-by-step explanation:

In cyclic quadrilateral sum of opposite angles = 180°

Hence < BCB = 140°